Home » All Calculators » Engineering Tools » Deflection For Square Tubing Calculator

Deflection For Square Tubing Calculator

Photo of author
Published on

A deflection calculator for square tubing helps engineers and builders figure out how much a square tube will bend under a load. This is important for ensuring the strength and stability of structures like bridges, buildings, and even furniture. By using this calculator, you can predict how the tube will behave when weight is applied to it, which helps in designing safe and efficient structures.

Purpose and Functionality of the Calculator

The purpose of this calculator is to measure the deflection, or bending, of square tubing. Deflection depends on several factors, such as:

  • The material’s stiffness (Young’s Modulus)
  • The tube’s dimensions and wall thickness
  • The length of the tube
  • The type and position of the load

How the Calculator Works

The calculator uses specific formulas from structural engineering to compute deflection. There are different formulas based on the type of load applied:

  1. Center Point Load: This is when a single load is applied at the center of the beam.
  2. Uniformly Distributed Load: This is when the load is spread evenly along the entire length of the beam.

To use the calculator, you need to input the following:

  • E (Young’s Modulus): A constant that measures the material’s stiffness.
  • I (Moment of Inertia): This depends on the outer dimension of the tube (b) and the wall thickness (t). The formula is: I=b4−(b−2t)412I = \frac{b^4 – (b – 2t)^4}{12}I=12b4−(b−2t)4​
  • L (Length of the Beam): The total length of the square tubing.
  • W (Load): The load applied, which could be at the center or uniformly distributed.

Formulas for Deflection

Here are the formulas based on the type of load:

Center Point Load

For a beam with a point load PPP at the center, the deflection δ\deltaδ at the center is given by: δ=P⋅L348⋅E⋅I\delta = \frac{P \cdot L^3}{48 \cdot E \cdot I}δ=48⋅E⋅IP⋅L3​

Uniformly Distributed Load

For a beam with a uniformly distributed load www (load per unit length), the deflection δ\deltaδ at the center is: δ=5⋅w⋅L4384⋅E⋅I\delta = \frac{5 \cdot w \cdot L^4}{384 \cdot E \cdot I}δ=384⋅E⋅I5⋅w⋅L4​

Example Calculation

Let’s calculate the deflection for a square tubing with the following specifications:

  • E = 210 GPa (for steel)
  • Outer dimension (b) = 100 mm
  • Wall thickness (t) = 5 mm
  • Length (L) = 3000 mm
  • Load (W) = 500 N (center point load)

Step-by-Step Calculation

  1. Calculate the Moment of Inertia (I): I=1004−(100−2×5)412I = \frac{100^4 – (100 – 2 \times 5)^4}{12}I=121004−(100−2×5)4​ I=1004−90412I = \frac{100^4 – 90^4}{12}I=121004−904​ I=100000000−6561000012I = \frac{100000000 – 65610000}{12}I=12100000000−65610000​ I=3439000012I = \frac{34390000}{12}I=1234390000​ I≈2865833.33 mm4I \approx 2865833.33 \, \text{mm}^4I≈2865833.33mm4
  2. Apply the Formula for Center Point Load: δ=500⋅3000348⋅210×103⋅2865833.33\delta = \frac{500 \cdot 3000^3}{48 \cdot 210 \times 10^3 \cdot 2865833.33}δ=48⋅210×103⋅2865833.33500⋅30003​ δ≈500⋅2700000000048⋅210000⋅2865833.33\delta \approx \frac{500 \cdot 27000000000}{48 \cdot 210000 \cdot 2865833.33}δ≈48⋅210000⋅2865833.33500⋅27000000000​ δ≈1350000000000028800000000000\delta \approx \frac{13500000000000}{28800000000000}δ≈2880000000000013500000000000​ δ≈0.46875 mm\delta \approx 0.46875 \, \text{mm}δ≈0.46875mm

This calculation shows that the deflection at the center of the beam under the given load is approximately 0.46875 mm.

Relevant Information Table

ParameterSymbolValueUnit
Young’s ModulusE210GPa
Outer Dimensionb100mm
Wall Thicknesst5mm
Length of the BeamL3000mm
Load (Center Point)W500N
Moment of InertiaI2865833.33mm^4
Deflection (Center Load)δ0.46875mm

Conclusion

Using a deflection calculator for square tubing is essential for ensuring that structures are both safe and efficient. By understanding how to input the necessary parameters and apply the correct formulas, you can accurately predict the deflection of the tubing under various loads. This helps in designing structures that can withstand applied forces without excessive bending, ensuring stability and safety in practical applications.

Leave a Comment